Beginning+Congruence

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Great job Ashley. You are a thourough scribd. Dave: I like Ashley's concise proof of Proposition 3.2. However, I think that the following statement requires justification: If AB is congruent to AC, then AC is congruent to AB. None of the axioms explicitly make this statement. The statement is nonetheless true. Axiom C-2 states in part that every segment is congruent to itelf. Combine this assertion with the other statement of Axiom C-2 to get the following: If AB is congruent to AC, and AB is congruent to AB, then AC is congruent to AB. 